(12/x^2+5x+6)+7/(x+3)=2/(x+3)

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Solution for (12/x^2+5x+6)+7/(x+3)=2/(x+3) equation: 



(12/x^2+5x+6)+7/(x+3)=2/(x+3)

We move all terms to the left:

(12/x^2+5x+6)+7/(x+3)-(2/(x+3))=0



Domain of the equation: x^2+5x+6)!=0

x∈R





Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: (x+3))!=0

x∈R



We get rid of parentheses

12/x^2+5x+7/(x+3)-(2/(x+3))+6=0

We calculate fractions

We do not support expression: x^3

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